How to create shell script with arguments

Question

How do I write a bash script that accepts command line arguments?

linux_expert · Accepted Answer

#!/bin/bash
# myscript.sh

# Access arguments
echo "Script name: $0"
echo "First arg: $1"
echo "Second arg: $2"
echo "All args: $@"
echo "Arg count: $#"

# Check if arg provided
if [ -z "$1" ]; then
    echo "Usage: $0 "
    exit 1
fi

# Named arguments with getopts
while getopts "n:v" opt; do
    case $opt in
        n) NAME="$OPTARG" ;;
        v) VERBOSE=true ;;
    esac
done

1 Answer